if 0.30 moles of magnesium nitrate reacts with 0.40 moles of sodium phosphate, how many moles of magnesium phosphate are formed?
Balanced chemical equation is:
3 Mg(NO3)2 + 2 Na3PO4 ---> Mg3(PO4)2 + 6 NaNO3
3 mol of Mg(NO3)2 reacts with 2 mol of Na3PO4
for 0.30 mol of Mg(NO3)2, 0.20 mol of Na3PO4 is required
But we have 0.40 mol of Na3PO4
so, Mg(NO3)2 is limiting reagent
we will use Mg(NO3)2 in further calculation
According to balanced equation
mol of Mg3(PO4)2 formed = (1/3)* moles of Mg(NO3)2
= (1/3)*0.30
= 0.10 mol
Answer: 0.10 mol
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