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if 0.30 moles of magnesium nitrate reacts with 0.40 moles of sodium phosphate, how many moles...

if 0.30 moles of magnesium nitrate reacts with 0.40 moles of sodium phosphate, how many moles of magnesium phosphate are formed?

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Answer #1

Balanced chemical equation is:

3 Mg(NO3)2 + 2 Na3PO4 ---> Mg3(PO4)2 + 6 NaNO3

3 mol of Mg(NO3)2 reacts with 2 mol of Na3PO4

for 0.30 mol of Mg(NO3)2, 0.20 mol of Na3PO4 is required

But we have 0.40 mol of Na3PO4

so, Mg(NO3)2 is limiting reagent

we will use Mg(NO3)2 in further calculation

According to balanced equation

mol of Mg3(PO4)2 formed = (1/3)* moles of Mg(NO3)2

= (1/3)*0.30

= 0.10 mol

Answer: 0.10 mol

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