Question

silver nitrate + sodium phosphate

+ sodium nitrate yields silver phosphate + sodium phosphate Ib. Silver nitrate Balanced: Complete lonic: Net Ionic: + sodium carbonate yields zine carbonate+ sodium nitrate 2a. Zinc nitrate (ag) (ag) Balanced: Complete lonic: Net lonic: 2b. Zinc nitrate (aq) + sodium phosphate yields zinc phosphate+ sodium nitrate (ag) () (a) Balanced: Complete Ionic: Net Ionic: Report Form - Chemical Reactions 50

Answer 1

1b answer

2 a answer is

Given reaction AgNO3(aq) + Na3PO4 (aq) ► Ag3PO4(s) + NaNO3(aq) Balanced equation is 3AgNO3(aq) + Na3PO4 (aq) → Ag3PO4 (s) + 3NaNO3(aq) This is molecular balance equation. Complete ionic equation: Write the soluble ionic compounds as dissociated ions, and non-soluble compounds expressed same as it is. 3Ag+ (aq) + 3NO, (aq) + 3Na (aq) + PO4 (aq) → 3Nat (aq) + 3NO; (aq) + Ag3PO4 (8) Net ionic equation Here we didn't change the representation of products Ag3PO4(s). In the complete ionic equation, we see that Na and NO3 is present on both sides of the reaction arrow. Ionic species are not changed in the reaction are called spectator ions. We can cancel out spectator ions from our complete ionic equation since they appear on both sides of the equation. Therefore net ionic equation is 3Agt (aq) + 2NO, the + 3Na Fe) + PO(aq) + 3Nu fac) + 2NO,"fe) + Ag3PO4 (8) 3Ag* (aq) + PO4 (aq) → Ag3PO4(s) (this is the net ionic equation) 3Agt (aq) + PO4 (aq) Ag3PO4 (s) (this is the net ionic equation)

Sodium carbonate (Na2CO3) and Zinc nitrate (Zn(NO3)2) Given reaction Na2CO3(aq) + Zn(NO3)2 (aq) → ZnCO3(aq) + NaNO3 (8) The Balanced molecular equation Na2CO3(aq) + Zn(NO3)2 (aq) → ZnCO3(s) + 2NaNO3 (aq) Total ionic equation Write the soluble ionic compounds as dissociated ions, and non-soluble compounds expressed same as it is. 2Nat (aq) + CO2 (aq) + Zn*- (aq) + 2NO; (aq) + 2Nat' (aq) + 2NO3 (aq) + ZnCO3 (8) Net ionic equation Representation of product ZnCO; (s), didn't change in the reaction, due to it is not soluble. In the complete ionic equation, we see that Nat' and NO, is present on both sides of the chemical reaction arrow. Ionic species are not changed in the reaction are called spectator ions. We can cancel out spectator ions from our complete ionic equation since they appear on both sides of the equation Therefore net ionic equation is 2N4* tue + CO 2 (aq) + Zn+2 (aq) + 2N0, -tuet + 2Na+ att + 2N10, the + ZnCO3 (8) co;(aq) + Zn+2 (aq) → ZnCO3(s) (this is the net ionic equation)