Question

4.2 Behavior of Gases Students will perform a simple reaction between NaHCO,+CH,COOH, or commonly known as baking soda and vinegar. In the pre-lab, students determine the moles of CO, by using the ideal gas law, PV=ORT where: P= Pressure (atm) V=Volume (lters...) n = moles (mol) T = Temperature (kelvin) R-Gas constant (atm:Imol:K) Students used STP, standard temperature and pressure, to determine their temperatures and pressure for this experiment. At STP, T = 273 K, and P 1 atm. Solve forn in the ideal gas law equation. From there, students used the stoichiometry of the reaction to determine the moles of NaHCO, _NaHCO,+ _CH,COOH > _NaCzH903 + _H20 + _CO2 Is this equation balanced? Using the equation, if the mole ratio between CH.COOH and NaC,H,O, IS 1:1, what is the mole ratio between NaHCO, and CO,? From here students will convert their moles of CO2 to moles of NaHCO3. mol CO2. - = mol of NaHCO, Students will then convert their moles of NaHCO, to grams of NaHCO,. Place in table 4.1, for trial 1. Students determined the weight of NaHCO, they calculated in pre la question 1 is the highest weight they can possibly use because this certain weight should produce 60 mL of CO2. The max volume the syringe they are using to capture the CO is 60 ml, so any more weight will theoretically be too much for the syringe. Students will also choose different weights below the weight they calculated in question 1 for trials 2 through 4, having a wide range in difference them to see how much CO, is being produced by the different weights. 1.) Determine the Mass of CO2

Answer 1

$\large \\Yes,\, \, it\, \ is\, \ a\, \ balanced \, \, equation.\\\\ NaHCO_{3}\, \ + \, \, CH_{3}COOH\Rightarrow NaC_{2}H_{3}O_{3}\, \ +\, \, H_{2}O\, \ + \, \ CO_{2}$

$\large \\From\, \,Stoichiometry\, \,,\\ \Rightarrow one \, \,mole. \, \, CO_{2}=one\, \, mole\, \,NaHCO_{3}$

$\large \\(a)\\$

Trial	Mass of NaHCO3 (g)	$\tiny moles \, \, of\, \, NaHCO_{3}=\frac{mass\, \, of\, \, NaHCO_{3}}{Molar\, \, mass\, \, of\, \, NaHCO_{3}}$
Trial 1
Trial 2	0.19	0.002262
Trial 3	0.15	0.001786
Trial 4	0.115	0.001369
Trial 5	0.75	0.008929

$\large \\(b)\\$

$\large \\From\, \,Stoichiometry\, \,,\\ \Rightarrow \, \,moles. \, of \, CO_{2}=\, \, moles\,of \,NaHCO_{3}$

$\large \\From\, \,Stoichiometry\, \,,\\ \Rightarrow \, \,moles. \, of \, CO_{2}=\, \, moles\,of \,NaHCO_{3}\\ Also, one\, \, mole\, \, of \, \, gas =\, 22.4\, \, L \, \, or\, \, 22400\, \, mL\, \, \, at\, \, STP\\$