Question

The mutual inductance between two coils is 0.0100 H. The current in the first coil changes uniformly from 2.70 A to 5.00 A in 0.160 s. If the second coil has a resistance of 0.600 Ohm, what is the magnitude of the induced current in the second coil?

For full points/best answer you must provide a thorough, explicit solution. Define all variables and derive all equations used. Thank you!

Answer 1

? = -M(dI1/dt)
(I2)(R) = -M(dI1/dt)
I2 = -(M/R)(dI1/dt)

I2 = -(1.00e-2 H / 0.600 ?)[(5.00 - 2.70 A)/0.160 s]
I2 = 0.240 A