here,
the initial velocity of car , u = 28.3 j m/s
time taken , t = 12 s
the final velocity of car , v = 14.1 j m/s
let the acceleration be a
using first equation of motion
v= u + a * t
14.1 j = 28.3 j + a * 12
solving for a
a = - 1.18 j m/s^2
the acceleration is 1.18 m/s^2 and towards South
A car is traveling north at 28.3 m/s. After 12 s its velocity is 14.1 m/s...
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