A car moves with an initial velocity of 19 m/s due north. Part A Find the velocity of the car after 5.6 s if its acceleration is 1.6 m/s2 due north Part B Find the velocity of the car after 5.6 s if its acceleration is 1.5 m/s2 due south.
Here,
let east is the positive x direction
north is the positive y direction
initial velocity , u = 19 j m/s
a)
acceleration , a = 1.6 j m/s^2
Using first equation of motion
v = u + a * t
v = 19 + 5.6 * 1.6
v = 28 j m/s
the velocity of the car after 5.6 s is 28 m/s north
b)
acceleration , a = -1.5 j m/s^2
Using first equation of motion
v = u + a * t
v = 19 - 5.6 * 1.5
v = 10.6 j m/s
the velocity of the car after 5.6 s is 10.6 m/s
north
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