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Based on an indication that mean daily car rental rates may be higher for Toronto than for Montreal, a survey of eight car re

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Answer #1

Below are the null and alternative Hypothesis,
Null Hypothesis, H0: μ1 = μ2
Alternative Hypothesis, Ha: μ1 > μ2

Rejection Region
This is right tailed test, for α = 0.05 and df = n1 + n2 - 2 = 15
Critical value of t is 1.753.
Hence reject H0 if t > 1.753

Pooled Variance
sp = sqrt((((n1 - 1)*s1^2 + (n2 - 1)*s2^2)/(n1 + n2 - 2))*(1/n1 + 1/n2))
sp = sqrt((((8 - 1)*4^2 + (9 - 1)*4^2)/(8 + 9 - 2))*(1/8 + 1/9))
sp = 1.9437

Test statistic,
t = (x1bar - x2bar)/sp
t = (50 - 42)/1.9437
t = 4.12

P-value Approach
P-value = 0
As P-value < 0.05, reject the null hypothesis.

The decision is to reject H0

are significantly more than those in Montreal

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