aString = 'Springsteen, Springsteen, oh, Springsteen!' aList = aString.split() bossCount = 0 for word in aList:...
aString = 'Springsteen, Springsteen, oh, Springsteen!' aList = aString.split() bossCount = 0 for word in aList: if word == 'Springsteen': bossCount += 1 print(bossCount) a. 0 b. 1 c. 2 d. 3 e. None of the above
Homework Answers
output:
a. 0
explanation:
as spli() is given without any delemeter so the string is splited as
"Springsteen,"
"Springsteen,"
"oh,"
"Springsteen!"
The search word is given "Springsteen" so not matched at all
So output will be be 0 which is the initial value of bossCount.
if search word is "Springsteen," then output is 2
Add Answer to:
aString = 'Springsteen, Springsteen, oh, Springsteen!' aList =
aString.split() bossCount = 0 for word in aList:...
def selectionSortK(alist, k): for i in range(0,len(alist) - 1): min = i for j in range(i + 1, len(alist)): if alist[j] < alist[min]: min = j temp = alist[i] alist[i] = alist[min] alist[min] = temp...
def selectionSortK(alist, k):
for i in range(0,len(alist) - 1):
min = i
for j in range(i + 1, len(alist)):
if alist[j] < alist[min]:
min = j
temp = alist[i]
alist[i] = alist[min]
alist[min] = temp
P3: Sanity Test: Is selectionSortK callable? ... ok
test_doNothing (__main__.TestProblem3)
P3: Does sorting the first k elements with k=0 do nothing? ...
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test_onePass (__main__.TestProblem3)
P3: Sorting a portion of a decreasing list ... FAIL
test_severalPasses (__main__.TestProblem3)
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RM-Q25 Match the following structures with their correct name. OH 0 n ОН ОН 1) 2) OH ОН 3) 4) OH o Drag and drop options on the right-hand side and submit. For keyboard navigation... Show More 1) = (39 4S)-3-hydroxy-4-phenylnonanoic acid 2) (3R 4R)-3-hydroxy-4-phenylnonanoic acid 3) III 1-ethylcyclohexane-3-carboxylic acid 4) III 3-ethylcyclohexanecarboxylic acid (E) 5-ethyl-3-methylhept-3-enoic acid RM-Q25 Match the following structures with their correct name. OH 0 ОН ОН 1) 2) OH ОН 3) 4) OH o Drag and...
def selectionSortK(alist, k):
for i in range(0,len(alist) - 1):
min = i
for j in range(i + 1, len(alist)):
if alist[j] < alist[min]:
min = j
temp = alist[i]
alist[i] = alist[min]
alist[min] = temp
P3: Sanity Test: Is selectionSortK callable? ... ok
test_doNothing (__main__.TestProblem3)
P3: Does sorting the first k elements with k=0 do nothing? ...
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test_onePass (__main__.TestProblem3)
P3: Sorting a portion of a decreasing list ... FAIL
test_severalPasses (__main__.TestProblem3)
P3: Sorting a decreasing list in several stages...
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41. Find O! A) 1 B) O C) -1 0 2 E) None of the Above 42. Find P2 A) 120 B) 10 C) 3 D) 20 E) None of the Above 43. Find.cz A) 120 B) 10 C) 3 D) 20 E) None of the Above 44. Find the missing probability. 0 2 1 3 X 4 p(x) 0.12 0.13 0.27 ? 0.09 A) 1 B) 1.61 C) 0.39 D) 0.43 E) None of the Above 45. Find 4!...
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