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A test model for a new type of braking system is designed to apply a braking force that decays following an exponential funct
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a = Voe At acceleration, a de = d (voe At ) a=- AVE ME 0 -A6 A) - A A+ A - AV - At force, Fama=-MAVO e V = Voe-At TuolistanceTaking logarithm on both sides, .. 2+ = log 5000 = 3.699. - t = 3.699 = 1.849 see (7) Initial breaking force F=-MA VOCAL I fr

answered by: ANURANJAN SARSAM
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