Question

plesse help we are using Kirchhoff's rule i am completely lost

(1) Five resistors are connected to an ideal battery as shown in this picture. Determine the current in each resistor. 2012 20.12 m m 1012 M M 4012 1012 10 V

Answer 1

9-220л. Division of current Y3 sor x+3 junctions A, C, F, E using function Law, 4or ton xty V F xty JOV G. (wing potential differene), O ning loop law For A B CFA -20y - 103 + 10x = 0 .-29 -3 +46 For loop CDEFC - 20(4-3) + lo(x+8) + 10 z=0 -2y +23 + x +3+3=0 -2y + 4z +x=0 for loop B C D G AB -204-20(y-7) +10=0 get - 2y-2y + 2z+60120 23 – 4y +120 = o per 2x0 O ĐA 4P From aj x= 2y tz x22xt to - A Subtract 4.x) from équition (1) +6y - 173 20 From W 23 equations 32 3/28 A y = 73 x 3/28 y = 17A y2 17/56A y zo 17 / 44 er brouch za 3/28A AP brouch x2-43+2y Febranch XtZ = 16A Be brouch CD borach IN - 12 + 34 2 55 #

Rz K Page No. : lam ул. y ity to v If reading of uzeo then the above Bet up is a balanced wheatstone bridge RI (resistances ratio of adjacent arm R4 = R, R eghat) R2 R3 Ru is curred in R, 6 R2 is sane surrent in Rat Ry is same