A huge 3.0-F capacitor has enough stored energy to heat 3.7 kg of water from 20...

Question

Question

A huge 3.0-F capacitor has enough stored energy to heat 3.7 kg of water from 20 ∘C to 95 ∘C

Part A

What is the potential difference across the plates? The specific heat of water is 4186 J/(kg⋅C∘).

Express your answer to two significant figures and include the appropriate units.

Answer 1

Answer #1

V = potential difference

C = capacitance = 3 F

$\Delta$ T = change in temperature = 95 - 20 = 75

c = specific heat = 4186

m = mass = 3.7 kg

Energy stored by capacitor = Heat

(0.5) CV² = m c $\Delta$ T

(0.5) (3) V² = 3.7 x 4186 x 75

V = 8.8 x 10² volts

Answer 2

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