Question

4. Suppose that a student performed the experiment and calculations perfectly as directed except that, unknown to the student, the balance was not zeroed but weighed 0.100 g too high throughout the experiment. Would the calculated val- ue for the density of the unknown liquid be correct? That is, would it be equal to, higher than, or lower than the true value. Explain your answer in clear and correct English.

Answer 1

density ( g/mL) = mass /Volume

4.

wt. of liquid = wt. of beaker with liquid - wt. of beaker = m

if balance was not zeroed and weighed 0.100 g more throughout experiment ,

wt. of liquid = (wt. of beaker with liquid + 0.100 g) - (wt. of beaker+ 0.100 g) = m

since , measured wt. or mass of liquid is difference of two values , thus there will be no impact on mass of liquid , thus ==> calculated value for density will be correct : equal to true value.

5. same error of balance in determination of density of Metal cylinder,

d = m/ V

if balance was not zeroed and weighed 0.100 g more during experiment ,

wt. of meat cylinder = m + 0.100 g

thus, d = m+ 0.100 g / V   > m/ V

since , measured mass of metal cylinder is difference more than actual , thus ==> calculated value of density for metal will be incorrect : higher than true value.