Question

Problem 6 - Part A The following dc measurements were made on the resistive network shown in (Figure 1). Measurement 1 Measurement 2 Vi = 4V Vi= 20 mV 11 =5 mA 1 = 20 A V2 = 0 V2=40 V 12 = -200 mA 12 = 0 Find the maximum power. Express your answer to three significant figures and include the appropriate units. Á O O ? Pamar = Value Units A variable resistor R is connected across port 2 and adjusted for maximum power transfer to R, Suppose that V, = 6.25 mV. Submit Request Answer < Return to Assignment Provide Feedback Figure < 1 of 1 > 2501 + Resistive network Pearson

Answer 1

to Givon circuit can be down as below im find maximum power Chevenins wvalent form Ren W1 w Val 250.12 I Resistive network 0 250+800 where. V The woning wivalent Wirage Roy - Thevenins cow Walent tregiglance atep:-1 From measurements 1, 2 make other masovements that makes = 6.25mv At post 1 zin me = 80012 by Schost cistaiting to terminals V = 4y đen k = 4 x355 đe) . 5-85V When Vg = 6.85 m2 Vi = va x450 800 - 100 V - 4.762 mv Multiply measurement with 25 x103 V = 4.768 mv. - From the concept of Linedily and -4.761991 Homoginity I, - 5.9523841 Va = 0 Ta --0,238.095mA I -- Tee -0.238095 mA Step-2 Same analysis for massement de Vi - LOMA. Z y = 1006-12 І - Хоан V = V x 100 taso = 25mV when Vg -6.25mV then find all the remaing parameters, Multiply every element with () V = 5mv Is = 5MA V = 8V V = Voc = 8V Voc = Ven=8V ZH = Ren = Voc S = 33.6k2 Tisc 0238095 Step-3- Ta =0

= 33.6ks According to maximum Power fromuster theorem. Po Consumes maximum Ven=8V Power only when Ro=Rth 3. wam Ro = 33.6K2 = 33.6 K2 4 Rth 4 (33.6) 0.9toimW Pmax = 0.47619 mw|