molar mass of methane = 16 g/mol then 8 gm methane = 8/16 = 0.5 mole
molar mass of ethane = 30 g/mol then 18 gm ethane = 18/30 = 0.6 mole
now calculate total mole of gas by using ideal gas equation
Ideal gas equation
PV = nRT where, P = atm pressure= 4.60 atm,
V = volume in Liter = 10 L
n = number of mole = ?
R = 0.08205L atm mol-1 K-1 =Proportionality constant = gas constant,
T = Temperature in K = 230C = 273.15+ 23 = 296.15 K
We can write ideal gas equation
n = PV/RT
Substitute the value
n = (4.60X 10)/(0.08205 X 296.15) = 1.9 mole
total mole of gas = 1.9 mole
mole of propane = total mole - mole of methane - mole of ethane
mole of propane = 1.9 - 0.5 -0.6 = 0.8 mole
now calulate mole fraction of each gas
mole fraction = no. of mole of insivisual gas / total mole
mole fraction of methane = 0.5 / 1.9 = 0.2632
mole fraction of ethane = 0.6 / 1.9 = 0.3158
mole fraction of propane = 0.8 / 1.9 = 0.421
now calculte partial pressure of each gas
partial pressure = mole fraction X total pressure
partial pressure of methane = 0.2632 X 4.60 = 1.2 atm
partial pressure of ethane = 0.3158X 4.60 = 1.5 atm
partial pressure of propane = 0.421 X 4.60 = 1.9 atm
9of11 Part A Three gases (8.00 g of methane, CH, 18.0 g of ethane, C2H6, and...
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