Question

Dalton's law states that the total pressure. Patel of a mixture of gases in a container equals the sum of the pressures of each individual gas: Part A P la P +1 +P: +.. The partial pressure of the first component. P. is equal to the mole fraction of this component, XI. times the total pressure of the mixture: P1= X X X Three gases (8.00 g of methane, CH,. 18.0 y of ethane, C,Hand an unknown amount of propane, CyH) were added to the same 10.0-L container. At 23.0 °C, the total pressure in the container is 4.50 al mm. Calculate the partial pressure of each gas in the container. Express the pressure values numerically in atmospheres, separated by commas. Enter the partial pressure of methane first, then ethane, then propane. ► View Available Hints) The mole fraction. X, represents the concentration of the component in the gas mixture, SO 12¢0 ? X -moles of componenti total moles in mixture atm Submit Previous Answers * Incorrect; Try Again: 5 attempts remaining - Part B A gaseous mixture of O, and N, contains 39.8 % nitrogen by mass. What is the partial pressure of oxygon in the mixture if the total pressure is 625 nully? Express you answer numerically in millimeters of mercury. View Available Hints) AXORO ? Payson = mully

Answer 1

vor forog2latmmaltkat) (2376+2131K 1.85 mol 6 According to ideal gas equation noor = PV (4650afm) x ( 100 OL) = 1085" polese Pettel = 18:0/16 7984x (40150 afm) = 22 okt = -2! akty Perhiel = (189/seg medl. x (180 akm) = 9:46 am males of propane. = 185-$(2) + (.) 1 = 0075 mal Petersen = (0.75 mol x (45oating = 1882 part B Moles of N2 = 38 mal = 1.42 mal ū O2 ='71002398mol = 1.88 mal 185 BONI 19N2) = The 1042 m nd (1642 1088 x 625 mmity = 269 mung Bozl= 1088_ 625 mm lang = 3568 withing (1042+188)