28. H1:σ < 0.629, n=19, α = 0.025
it is a one(left) tailed test. with df = 19-1=18
Critical value using excel =
=CHISQ.INV(0.025,18)
= 8.231
Option 1st.
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29.
Answer
Option 3rd
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26.
Option 4th
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27. two tailed test, df = 28-1=27
Critical value using excel =
Lower value =CHISQ.INV.RT(0.975 ,27) = 14.573
Upper value =CHISQ.INV.RT(0.025 ,27) = 43.194
Option 4th
S. Find the critical value or values of χ2 based on the given information. (1 point)...
Find the critical value or values of χ2 based on the given information. H1 : σ < 0.629 n = 19 α = 0.05 Group of answer choices a) 28.526 b) 31.526 c) 9.39 d) 8.231
Find the critical value based on the given information. Н. 0 < 0.629 n = 19, a = 0.025. 8.907 31.526 O 7.015 8.231
Help please Statistics 50 Test 4A Chapters 8 Fall 2009 Page 3. Find the critical value or values ofx 2 based on the given information. 7) H1:0<0.629 n- 19 ?-0.025 A) 31.526 B) 8.907 C) 8.231 D) 7.015 Use the traditional method to test the given hypothesis. Assume that the population is normally distributed and that the sample has been randomly selected 8) A machine dispenses a liquid drug into bottles in such a way that the standard deviatian of...
Find the critical value of x2 based on the given information H1:0< 1000 629 n = 20 a = 0.025 H1:0 629 1000 n = 20 a = 0.025 8.231 32.852 8.907 9.591
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please help Find the critical value and rejection region for the type of chi are test with sample size n and level of significance a. Two-tailed test n 12, a- 0.05 x2L = 4.575-X2R = 1 9.675; x2 < 4.575, x2 > 19.6 OX2L=3.816.x2R= 21.920-X2< 3.81 6.x2-1.920 。X2L = 2.603, X2R = 26.757: Χ2 < 2.6c x2 > 26.757 X2L = 3.053, X2R = 24.725; X2 ,053-X2 > 24.725 .5 QUESTION 22 Find the rejection region for the specified hypothesis...
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