Question

Question 1 15 pts PB PC PD B) с D tor Ta А E LAB LBC LCE LED For the beam and loading shown draw a shear and moment diagram then determine the minimum required width b, knowing that for the grade of timber used, the maximum allowable normal stress is 12 MPa and the maximum allowable shear stress is 822 kPa. The dimensions are the following: a = 148 mm, LAB = 0.9 m, LBc = 1.1 m, LcE = 1.1 m, LED = 0.5 m, and the loading is PB = 2.3 kN, Pc = 4.7 kN, and Po = 7.2 kN.

For the beam and loading shown draw a shear and moment diagram then determine the minimum required width b, knowing that for the grade of timber used, the maximum allowable normal stress is 12 MPa and the maximum allowable shear stress is 822 kPa. The dimensions are the following: a = 148 mm, L_AB = 0.9 m, L_BC = 1.1 m, L_CE = 1.1 m, L_ED = 0.5 m, and the loading is P_B = 2.3 kN, P_C = 4.7 kN, and P_D = 7.2 kN.

Answer 1

BHA=0 BMB = 2.1387x0.9 = 1.92483.KN-m BMC 2.138712 – 2-3x101 = 1.7479 KN-m BME = - 72x0.5 = -3-6ko-m BMD max = 3.6 knom T=12 Mpa M Z 64 bar > be GM tar 6x366x106 12 x 1482 b. =82-176 mm SEA A = 2.1387 kW SEBE 2.1387-2.3 = -0.163 KN SFCE = -0-163-4.7-4.8613 KN SIDE = 7-2 kN.

Max sheal force F = 7.2 KN shear stress F aug А ab May shear stress = Nw 3 tang 1-2x103 822 1000 3 2 bx148 - b=88.7749 mm too criteria we have to Among take maximum b value b = - 88.775 mm Answer