Question

Use quadratic regression and a graphing calculator to find the quadratic function that best fits the data set. Then use the m

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Answer #1

from the x coordinate

matrix A and AT are

.

6 5 0 3 0 050567 051111

.

from the y coordinate

vector b is

422 389 350 324 325 919

.

take \large A^T*A

Ar A-(0 5 10 15 16 İ7)| 1 10 3 0510151617ノ1115 1 16 1 17

/6 63 895 ATA= 895

..

.

now take \large A^T*b

422 389 350 0 5 10 15 16 17 324 325 319 1 1

АТЬ (O 1424225-1389 910-3300 15 324 +16 3225 11731319) 0. 422+5 . 389+ 10. 350+ 15. 324 + 16. 325+17. 319

2129 ( 20928 47 b

.

.

solve for \large [A^T*A]x=[A^T]b

2129 20928 63 895m

augmented matrix is

6 63 2129
63 895 20928

convert into Reduced Row Eschelon Form...

Divide row1 by 6

1 21/2 2129/6
63 895 20928


Add (-63 * row1) to row2

1 21/2 2129/6
0 467/2 -2853/2


Divide row2 by 467/2

1 21/2 2129/6
0 1 -2853/467


Add (-21/2 * row2) to row1

1 0 586991/1401
0 1 -2853/467

reduced matrix is

3 1 0

586991 1401 13883

.

.

line is y=mx+c

.

{\color{Red} y=-\frac{2583}{467}x+\frac{586991}{1401}}

.

or

{\color{Red} y=--5.53x+418.98}

.

.

in 2007 take x=22

.

y - 5.53 - 22 + 418.98

y= -121.683+418.98

y= 297.29693

{\color{Red} y= 297}.............asnwer

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