Question

Constants| Periodic Table Part A In a cars suspension system, each wheel is connected to a vertical spring: these springs absorb shocks when the car travels on bumpy roads. In one car, each spring has a spring constant of 5.2 × 104 N/m f this 1300 kg car is driven at 25 m/s through the bottom of a circular dip in the road that has a these springs compress compared to when the car is driven on a flat road? radius of 625 m, by how much do Express your answer with the appropriate units Ayl-Value Units Submit Provide Feedback Next >

Answer 1

k = 5.2 times 10^4 N/m Compared to Flat road, on dip of the curve extra force exerted on springs will be because of movement of car in circular motion. Force exerted = F_ret = mv^2/R = 1300 times (25)^2/625 = 1300 N This is the force experienced by 4 spring force experienced by ore spring F = F_ret/4 = 325 N F = Kx k rightarrow spring constant) x rightarrow Extra compression 325 = 5.2 times 10^4 times x x = 325/5.2 times 10^4 x = 6.25 times 10^-3 m x = 6.25 mm