Consider the value of such that 0.05 of the area under the curve is to the...

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Answer 1

Answer #1

T-table:

25 31 765 .40 I) ,05 .025 .3251.CO) 3.786.3[ 12.706 289 ,816 1.886 2,92) 4.303 27 1.638 2.353 3.182 271 741 1533 2. 132 2.776

So, the value is 1.734

You need to go to DF = 18 and then select the value in the second column that should be 1.734.

Please comment if any doubt. Thank you.

Answer 2

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