pI is the pH at isoelectric point.
Only those pka are taken at which post protonation/ de-protonation
no charge remains. For here the pKa are 1.70, 10.74
pI=1/2(1.70+10.74)
pI=6.22
A solution of 0.181 M cysteine is titrated with 0.0453 M HNO_3. The pK_a values for...
1A solution of 0.235 M aspartic acid, the charge neutral form of the amino acid, is titrated with 0.118 M NaOH . The p K a values for aspartic acid are 1.990 , 3.900 , and 10.002 , corresponding to the α-carboxylic acid group, the β-carboxylic acid group, and the amino group, respectively. Calculate the pH at the first equivalence point of this titration.
A 55.0 mL solution of 0.111 M potassium alaninate ( H2NC2HCO2K) is titrated with 0.111 M HCI. The pKa values for the amino acid alanine are 2.344 (pKal) and 9.868 (pKa2), which correspond to the carboxylic acid and amino groups, respectively. Calculate the pH at the first equivalence point. CH3 H2N Potassium Alaninate Calculate the pH at the second equivalence point. pH
A 50.0 mL solution of 0.174 M potassium alaninate (H2NC2H5CO2K) is titrated with 0.174 M HCl. The pKa values for the amino acid alanine are 2.344 (pKa1) and 9.868 (pKa2), which correspond to the carboxylic acid and amino groups, respectively. a. Calculate the pH at the first equivalence point b. Calculate the pH at the 2nd equivalence point
A 70.0 mL solution of 0.120 M potassium alaninate (H2NC2H5CO2K) is titrated with 0.120M HCL. The pKa values for the amino acid alanine are 2.344 (pKa1) and 9.868 (pKa2), which correspond to the carboxylic acid and amino groups, respectively. a) Calculate the pH at the first equivalence point. pH = b) Calculate the pH at the second equivalence point. pH =
CH3 A 60.0 mL solution of 0.183 M potassium alaninate (H2NC,H,CO,K) is titrated with 0.183 M HCl. The pKa values for the amino acid alanine are 2.344 (pKal) and 9.868 (pKa2), which correspond to the carboxylic acid and amino groups, respectively. H2NCH——0 Calculate the pH at the first equivalence point. Potassium Alaninate pH = Calculate the pH at the second equivalence point. pH = ||
сн. A 75.0 mL solution of 0.146 M potassium alaninate (H, NC,H,CO,K) is titrated with 0.146 M HCl. The pK values for the amino acid alanine are 2.344 (PK) and 9.868 (pK22), which correspond to the carboxylic acid and amino groups, respectively. H2N- CH-C- Calculate the pH at the first equivalence point. Potassium Alaninate pH = Calculate the pH at the second equivalence point. pH =
A volume of 30.0mL of a 0.810\it M \rm HNO_3 solution is titrated with 0.340\it M \rm KOH. Calculate the volume of \rm KOH required to reach the equivalence point
A 75.0 mL solution of 0.132 M potassium alaninate (H2NC2H5CO2K) is titrated with 0.132 M HCl. The pKa values for the amino acid alanine are 2.344 (pKa1) and 9.868 (pKa2), which correspond to the carboxylic acid and amino groups, respectively. The alaninate ion is the basic form of the diprotic amino acid alanine. The alaninate ion reacts with a strong acid to form the neutral, amphiprotic, intermediate species at the first equivalence point. The intermediate species then reacts with the...
Calculate the pH of the solution after the addition of the following amounts of 0.0676 M HNO_3 to a 60.0 mL solution of 0.0750 M aziridine. The pK_a of aziridinium is 8.04. 0.00 mL of HNO_3 pH = 6.81 mL of HNO_3 pH = 62.6 mL of HNO_3 pH = Volume of HNO_3 equal to the equivalence point pH = Volume of HNO_3 equal to half the equivalence point volume 70.5 mL of HNO_3 pH =
Calculate the pH of the solution after the addition of the following amounts of 0.0577 M HNO_3 to a 80.0 mL solution of 0.0750 M aziridine. The pK_a of aziridinium is 8.04. a) 0.00 mL of HNO_3 pH b) 8.45 mL of HNO_3 PH = c) Volume of HNO_3 equal to half the equivalence point volume pH = d) 1.00 times 10^2 mL of HNO_3 pH = e) Volume of HNO_3 equal to the equivalence point pH = f) 109...