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A 75.0 mL solution of 0.132 M potassium alaninate (H2NC2H5CO2K) is titrated with 0.132 M HCl....

A 75.0 mL solution of 0.132 M potassium alaninate (H2NC2H5CO2K) is titrated with 0.132 M HCl. The pKa values for the amino acid alanine are 2.344 (pKa1) and 9.868 (pKa2), which correspond to the carboxylic acid and amino groups, respectively.

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The alaninate ion is the basic form of the diprotic amino acid alanine. The alaninate ion reacts with a strong acid to form the neutral, amphiprotic, intermediate species at the first equivalence point.

The intermediate species then reacts with the strong acid to form the positively charged, acidic species at the second equivalence point.

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PLEASE ANSWER ALL PARTS. THANK YOU!

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Answer #1

15o 259 866-30 40%- 03 500 60o 90% 10 68 68 68. 97 ベー pri

At second equivalence point ;

pH = (pKa1 +pKa2)/2 = (2.344+9.868)/2 = 6.106

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