Question

Site 1: 50.39 43.15 49.25 50.82 41.14 42.32 37.50 45.22 45.08 Site 2: 45.62 39.47 43.71 42.23 42.41 48.54 30.73 39.99 Site 3: 37.41 40.40 29.19 44.07 33.70 38.46 36.42 36.78 45.76 44.49 37.54 42.41 Site 4: 36.39 39.07 40.55 39.46 37.88 42.45 35.41 40.04 41.27 47.09 45.88 45.00 Which null hypothesis, Ho, will be used to test whether the mean salinity is the same at all four sites? Correct: P1=2=H3=14 Incorrect H1-H2-M3-M4=0 Incorrect H1+ 2+23+H4=0 Incorrect 11 + H2 + H3 + H4 [1 pt(s)] You are correct. Previous Tries Your receipt no. is 155-8741 What is the alternative hypothesis, HA? O H1 H2 H3 H4 # 0 H1 H2 H3 H4 O At least one wi is not equal to the rest. O H1+H2+H3+44 70 (1 pt(s)] Incorrect. Tries 1/1 Previous Tries Calculate the test statistic. 0.1439 [2 pt(s)] Submit Answer Incorrect. Tries 2/3 Previous Tries Which interval in the table contains the p-value for the test? (Verify your answer by calculting the p-value with statistical software and using the appropriate table on the course site. You might have to improvise a little with the tables if your exact degrees of freedom aren't listed.) O p-value < 0.001 O 0.001 < p-value < 0.01 O 0.01 < p-value < 0.05 O 0.05 < p-value < 0.1 O 0.1 < p-value < 0.25 O p-value > 0.25 [3 pt(s)] Submit Answer Tries 0/1 Would you reject the null hypothesis at a = 0.05? O Yes O No

Answer 1

applying ANOVA On above data:

Source of Variation	SS	df	MS	F	P-value
Between Groups	194.9784	3	64.9928	3.1555	0.0361
Within Groups	762.0878	37	20.5970
Total	957.0662	40

alternative hypothesis:

At least one w; is not equal to the rest.

test statistics =3.1555

0.01 < p-value < 0.05

would you reject the null : Yes