Question

Machine A performs an amount of work, W, in a time, t, and generates a power, P Machine B performs an amount of work, 2W, in a time, 2t. What power is generated by machine B? ○ 4P O P P/2 2P QUESTION 2 10 B A man pushes a wheelbarrow at an angle of 31 0 to the horizontal (0) with a force of 217 N. If the wheelbarrow moves a distance of 34.5 m across the horizontal ground, how much work does he do, in units of Joules?

Answer 1

Power = Energy/Time Energy is equivalent to the work done P = w/t P_A = w/t = P P_B = 2w/2t = w/t P_B = P. Second option is correct. W = F middot S = FS cos s theta = 217 times 34.5 times cos 31 degree = 6417.183 J W = F middot S (S is the displacement) = FS cos theta (theta is the angle b/w F & S) = F S (cos 0 degree) = FS W = 12 times 13 = 156 J \r\n W = F middot S = FS cos theta = FS cos 0 degree = FS = 1.2 times 3 = 3.6 J k = 1300 N/m x = 0.055 m U = 1/2 kx^2 (energy stored) = 1/2 times 1300 times (0.055)^2 = 1.96625 J
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