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A constant 74.6-N force acts on a 4.99-kg box. The box initially is moving at 15.1...

A constant 74.6-N force acts on a 4.99-kg box. The box initially is moving at 15.1 m/s in the direction of the force, and 2.93 s later the box is moving at 76.5 m/s. Determine the work (in J) done by this force. You may assume that the box experiences constant acceleration, but do not assume that only one force acts on the box.

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Answer #1

The constant force of 74.6 N is the net force acting on the box and the work it does is equal to the change in the kinetic energy of the box.

Using the work-kinetic energy theorem, relate the work done by the constant force to the change in the kinetic energy of the box:

W = KEf - KEi

W = (1/2)m (Vf2 - Vi2)

W = (1/2)*4.99kg*(76.52 - 15.12 )

W = 14032.47 J

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