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(12 pts) Use the table of z-scores and percentiles to find the percentage of data items in a normal distribution that: a. Lie
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Answer #1

a.

Lie above z =0.3

From the table : At z = 0.3 Z score is 11.79%

This score corresponds 0 < z < 0.3

above z =0.3 percentage of data items = (50-11.79)% = 38.21%

b.

Lie below z = -0.9

From the table : At z = -0.9 Z score is 31.59%

This score corresponds -0.9< z < 0

below z = -0.9 percentage of data items= (50-31.59)% = 18.41%

c.

Lie between z =-2 and z= -0.6

Percentage of data items = (47.72 - 22.57)% = 25.15%

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