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Use the normal distribution of IQ scores, which has a mean of 105 and a standard deviation of 17, and the following table wit

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Answer #1

µ = 105, σ = 17

P(X < 139) =

= P( (X-µ)/σ < (139-105)/17 )

= P(z < 2)

Using excel function:

= NORM.S.DIST(2, 1)

= 0.9772 = 97.72%

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