1) in this reaction less disordered state is form hence ∆S is negative (-) for this reaction. Because randomness increases entropy is positive and randomness decreases entropy is negative.
2) option C is correct. Randomness increases entropy also increases in option C randomness is more as compare to all other examples hence option C is correct.
Question 1 The sign for AS in the following reaction is CH2=CH2(g) + H2(g) - CH3CH3(g)...
Which of the following processes have a ΔS > 0? A) Na2CO3(s) + H2O(g) + CO2(g) → 2 NaHCO3(s) B)CH4(g) + H2O(g) → CO(g) + 3 H2(g) C)CH3OH(l) → CH3OH(s) D)N2(g) + 3 H2(g) → 2 NH3(g) E)All of the above processes have a DS > 0.
2. For the following example, identify the following.
H2O(l) → H2O(s)
question 2 options
a negative ΔH and a negative ΔS
a positive ΔH and a negative ΔS
a negative ΔH and a positive ΔS
a positive ΔH and a positive ΔS
It is not possible to determine without more information.
3. Calculate ΔS°rxn for the following reaction. The S° for each
species is shown below the reaction.
C2H2(g) + H2(g) →
C2H4(g)
S°(J/mol∙K) 200.9 130.7 219.3
Question 4 options:...
1. For the reaction 3 H2(g) + N2(g) → 2 NH, (g), 3 mol H2 is reacted with 6 mol N2- mol of NH3 is produced mol of Hy remains _mol Ny remains 2. For the reaction 2 N H (1) + N20 (1) 3N2(g) + 4 H 0 (), 160 g N,H, is mixed with 160 g N204 (Answer: 125 g H20) is the limiting reagent _g H2O is produced 3. For the reaction Fe203 (s) + 3 CO(g)...
1. Determine the ∆Sº using Appendix G for the following reaction. C2H5OH(l) + 3 O2(g) --> 2 CO2(g) + 3 H2O(l) Report your answer to three sig figs. Omit unit labels. Only add a - number is the sign is negative. Adding a + to a positive answer messes up the grading. 2. Which of the following equations will have a negative ∆S? A. 3 H2(g)+ N2(g) --> 2 NH3(g) B. C6H6(l)--> C6H6(g) C. NH4OH(s)--> H2O(l)+ NH3(g) D. NaCl(s) -->...
Which reaction is accompanied by an increase in entropy? A N2(g) + 3 H2(g) – 2 NH3(g) B. Ba(OH)2(s) + CO2(g) → BaCO3(s) + H2O(1) C. NH4NO2(s) – N2(g) + 2 H20(0) D.2 C2H2(g) + 5 O2(g) – 4 CO2(g) + 2 H2O(s) E. C8H16(1) + 12 O2(g) — 8 CO2(g) + 8 H 20(1)
3. Predict the sign (positive or negative) on the entropy change for each of these reactions. (a) 2 SO2 (g) + O2 (g) → 2 SO3 (g) Negative (b) 2 NH3 (g) → N2 (g) + 3 H2 (g) (c) CO (g) + 2 H2 (g) → CH3OH (1) 4. For the reaction: 2NO2 (g) + N204 (g) at 298 K, The value of AH° and AS™ are -58.03 kJ and -176.6J/K, respectively. (a) What is the value of AG°...
A reaction to produce “substitute natural gas” is described by: 4 CO (g) + 8 H2 (g) → 3 CH4 (g) + CO2 (g) + 2 H2O (l) Use the following information, as necessary, to estimate DH for the above reaction. 2 C (graphite) + O2 (g) → 2 CO (g)ΔfH= –221.0 kJ/mol 2 CO (g) + O2 (g) → 2 CO2(g)ΔrH= –566.0 kJ/mol 2 H2 (g) + O2 (g) → 2 H2O (l)ΔfH= –571.6 kJ/mol C (graphite) + 2...
Which is the correct equilibrium constant expression for the following reaction? 2 NaHCO3(s) Na2CO3(s) + CO2(g) + H2O(g) O A. Kc=[Na2CO3] / [NaHCO3)2 O B. Kc = [NaHCO3] 2 / [Na2CO3][ CO2][ H20] O C. Kc = [ CO2][ H20] OD. Kc = [Na2CO3][ CO2][ H20] / [NaHCO3)2
Calculate the enthalpy of the following reaction: C (s) + 2 H2 (g) --> CH4 (g) Given: C (s) + O2 (g) --> CO2 ΔH = -393 kJ H2 + 1⁄2O2 --> H2O. ΔH = -286 kJ CH4 + 2O2 --> CO2 + 2H2O ΔH = -892 kJ
Use the table to calculate the energy change in J/K of each reaction below (assume standard thermodynamic conditions 1.00 atm and 298.15 K) Substance S (J.mol -1. K -1 Br2 (l) 152.23 HBr (g) 198.59 C (diamond) 2.38 CH4 (g) 186.2 CH3OH (l) 126.8 CO (g) 197.6 CO2 (g) 213.6 O2 (g) 205.0 H2 (g) 130.6 H2O (g) 188.7 N2 (g) 191.5 NO (g) 210.7 NH3 (g) 192.3 NO (g) 210.7 NO2 (g) 240.0 K2CO2 (s) 155.52 KOH (s) 78.91 S (rhombic) ...