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Score: 9 09%, 1 of 11 Score: 0 of 1 pt 9 of 11 (2 complete) 10.3.33-T Question, Heip Suppose the mean IQ score of people in a
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Answer #1

Solution :

\mu= 103

\bar x = 107.8

S = 13.7

n = 42

This is the two tailed test .

The null and alternative hypothesis is ,

H0 :  \mu = 103

Ha : \mu > 103

Test statistic = T

= (\bar x - \mu ) / S / \sqrt n

= (107.8-103) /13.7 / \sqrt 42

= 2.27

P(z > 2.27) = 1 - P(z < 2.27) = 0.0142

P-value = 0.0142

\alpha = 0.05  

p = 0.0142 < 0.05, it is concluded that the null hypothesis is rejected..

There is enough evidence to claim that the population mean μ is greater than 103, at the 0.05 significance level.

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