Question

j12 _12 -j1༽ -10

Answer 1

Slution in jin in a inn NV - jln Note that upper in and ju ar in series, which results to (14 31) n. . This is parallel to n+(-510n which results to 0 +) C1-3). 1-4-1) = in. +8+18 m jln -jln to wye /star change delta network we need to network. . ZKA 4 . - R3 W RI - RC 27 . RC= R2 for delta - stay connection; RA = R3 RI RT R₂ + Ry pe R R2 R1 + R2 + R Rit R2 + R3

Take the center a connection IA mir B . - kalu { RC = ju RA= (31) (-31) j-5+1 RB = (14) (-5W) - RC = (10) (M) - jn. Eli jln . - jln . In and sin are ch. series = (1+i)n In and fin are in series =) (1-31) (itin (1-3jn

(143) s (1-9)us (in) are forming T-network. TuwzB mmo Senas om R2 = RARB + RB Rc + RC RA RA · R3 = RARB + RBRC + RCRA . R3 = RARO RB R = RARB + RBKC + RCRA BB - RC R = (1-3)(I) + (-5) C1+3)(1+j) (1) - PI = 1-+ 2 +1+3 = .9 I+ j 1t -jln Gia C-ji) one parallel = city (0) - 54 Guy - ) 9-ŚCis) ( -94

( 4 ) Pinjane parallel 3 + - + 1 2+j 3-1 = 4; (1-3-1-) ) = 45 (02 uu Lab a to b The equivalent impedence from is Rab = "ca