Question

A 300 gram piece of aluminum is heated in an oven until its temperature is 370 K. It is transferred to an insulated container containing 2 kg of water at 290 K and then sealed. Later, when the container

Answer 1

Let T be the Equlibrium temperature:

Now Heat lost by Aluminium piece = Heat gained by water:

$Q_{Al}=Q_{water}$

mA1CA1(370-T) n uatercuater (T-290)

300 * 1 * (370-T) 2000 * 4.2 * (T-290)

(370-T) 28(T-290)

370-T 287.-8120

$\Rightarrow 29T=8490$

$\Rightarrow T=292.76K$

Hence at equilibrium, the temperature of water =292.76K