A 110-V electric iron draws 3.0 A of current. How much thermal energy is developed each...

Question

Question

A 110-V electric iron draws 3.0 A of current. How much thermal energy is developed each hour?

Answer 1

Answer #1

V = IR

so R = V / I =110V / 3.0A = 37 $\Omega$

and Q = E = I²Rt = (3.0 A)²(37 $\Omega$ )(1 h)(3600s/h) = 1.2 x 10⁶ J

luck !

Answer 2

Answer #2

ohms law, here v is the voltage, l is the current, R is the resistance び110び 1 3.0A R 36.660 Thermal energy. E-12 Rt-G.0AY *

Answer 3

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