The future value can be calculated by the following formula:
Where r is the rate of interest and n is the number of periods left.
Putting the values:
Therefore, future worth is equal to $51,735 (approximately). The correct answer is 'Option B'.
PREGUNTA 3 What is the future worth in year 10 of $5,000 at 1-0,510,000 at 1-...
Its an economics engineering question 3. Determine the future worth at the end of year 10 of a cash flow series that starts 2 years from now at $125,000 and decreases by 8% per year. Use an interest rate of 8% per year. (20) 3. Determine the future worth at the end of year 10 of a cash flow series that starts 2 years from now at $125,000 and decreases by 8% per year. Use an interest rate of 8%...
4.54 What is the future worth in year 8 of a present sum of $50,000 if the interest rate is 10% per year in years 1 through 4 and 1% per month in years 5 through 8?
The future worth in year 10 of an arithmetic gradient cash flow series for years 1 through 10 is $500,000. If the gradient, G, increases each year at $3,000 per year, determine the present worth of the uniform series only, at an interest rate of 10% per year.
What is the future value at the end of year 28 of depositing $5,000 today, $3,500 at the end of years 1, 2 and 3, $5,000 at the end of years 4, 5, 6 and 7 and $4,250 at the end of years 8, 9, 10, 11 and 12 into an account that pays 9.5% p.a.? (No deposits will be made into the account after year 12).
The future worth in year 10 of an arithmetic gradient cash flow series for years 1 through 10 is $700,000. If the gradient increase each year, G, is $2750, determine the cash flow in year 1 at an interest rate of 10% per year.
future worth. 2.84 Calculate the annual cost for years I through 9 of the following series of disbursements. Use an in- terest rate of 10% per year. Solve using (a) factors and (b) a spreadsheet. Year Disbursement, $ Year Disbursement,$ 5,000 4,000 4,000 4,000 4,000 0 5,000 5,000 5,000 5,000 5,000 4 2 Nippon Steel's expenses for heating and cooling one of its large manufacturing facilities are expected to increase according to an arithmetic gradient beginning in year 2. The...
What is the future worth of a series of equal year-end deposits of $2.900 for 10 years in a savings account that earns 7% annual interest if the following were true? (a) All deposits are made at the end of each year? (b) All deposits are made at the beginning of each year? Click the icon to view the interest factors for discrete compounding when i: 7% per year. (a) The future worth of a series of equal year-end deposits...
23. What is the future value at the end of year 28 of depositing $5,000 today, $3,500 at the end of years 1, 2 and 3, $5,000 at the end of years 4, 5, 6 and 7 and $4,250 at the end of years 8, 9, 10, 11 and 12 into an account that pays 9.5% p.a.? (No deposits will be made into the account after year 12). 24. If you wanted to fund a scholarship that would pay $12,500...
The future worth in year 10 of an arithmetic gradient cash flow series for years 1 through 10 is $575,000. If the gradient increase each year, G, is $1750, determine the cash flow in year 1 at an interest rate of 11% per year. The cash flow in year 1 is $ .
Hand-written solution is what is needed Check my work 2 o Required information Future worth, F, has to be found from a present amount, compounded quarterly. Part 1 of 3 five years from now at an interest rate of 12% per year, 5.55 points What interest rate must be used in the FiPfactor, (FIP,Po,n), when n is 5? The interest rate that must be used in the FIP factor, (FIP.P%,n),when n is 5 is eBook Hint Print References