The excitation table of T-Flip Flop.
Q | Q+ | T |
0 | 0 | 0 |
0 | 1 | 1 |
1 | 0 | 1 |
1 | 1 | 0 |
STATE DIAGRAM.
A (00) - represents 0's even and 1's even
B(01) - represents 0's even and 1's odd
C(10) - represents 0's odd and 1's even
D(11) - represents 0's odd and 1's odd.
State table
Q1 | Q0 | X | Q1+ | Q0+ | T1 | T0 | Z |
0 | 0 | 0 | 1 | 0 | 1 | 0 | 0 |
0 | 0 | 1 | 0 | 1 | 0 | 1 | 0 |
0 | 1 | 0 | 1 | 1 | 1 | 0 | 1 |
0 | 1 | 1 | 0 | 0 | 0 | 1 | 0 |
1 | 0 | 0 | 0 | 0 | 1 | 0 | 0 |
1 | 0 | 1 | 1 | 1 | 0 | 1 | 1 |
1 | 1 | 0 | 0 | 1 | 1 | 0 | 0 |
1 | 1 | 1 | 1 | 0 | 0 | 1 | 0 |
K-MAPS
Q1 Q0 | 00 | 01 | 11 | 10 |
X=0 | 0 | 1 | 3 | 2 |
X=1 | 4 | 5 | 7 | 6 |
FOR T1
Q1 Q0 | 00 | 01 | 11 | 10 |
X=0 | 1 | 0 | 0 | 1 |
X=1 | 1 | 0 | 0 | 1 |
mapping quad 0,2,4,6
T1 = Q0' ( compliment of Q0)
FOR T0
Q1 Q0 | 00 | 01 | 11 | 10 |
X=0 | 0 | 1 | 1 | 0 |
X=1 | 0 | 1 | 1 | 0 |
mapping 1,3,5,7
T0 = Q0
FOR Z
Q1 Q0 | 00 | 01 | 11 | 10 |
X=0 | 0 | 0 | 0 | 1 |
X=1 | 0 | 1 | 0 | 0 |
Z = X' Q1 Q0' + X Q1' Q0.
CIRCUIT DIAGRAM
At left, T0 flip flop and right one is T1 Flip flop.
THANK YOU
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