Question

4) While reading a journal article, you come across the results of an ANOVA, reported as F(3,32) = 4.61. Having read earlier
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Answer #1

Solution

a)Number of groups are 4 because

Here F(3,32) , 3 indicates degrees of freedom for group so it is given by = Total number of group – 1 = 4- 1 =3

So Number of groups are 4

c) Observations were there in total are 36

Because total degrees of freedom are n-1

degrees of freedom = degrees of freedom group + degrees of freedom error

degrees of freedom = 3+32 = 35

so

n-1 = 35

n = 36

b)since groups are equal in size

so

there are total 4 groups so

n/4 = 36/4 = 9

Number of observations are 9

d) The p-value is .008618

As p-value < 0.05 level of significance so we conclude that all groups do not equal mean

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