Question

Question Help Show a The following data represent the dividend yields (in percent) of a random sample of 28 publicly traded stocks. Complete parts (a) to (c). 26 0.27 0.58 0.15 2.77 3.45 0.250 0.531.29 2.160 0.46 0.29 0.83 0 0.182.65 2.92 2.83 0.29 3.14 .93 0.52 0.03 0.36 0 0.13 0 (a) Compute the five-rumber summary The five number summary is 1:000 0 (Round to two decimal places as needed. Use ascending order)

Answer 1

The 5 number summary of the data values:

Min: 0
1st quartile: 0.165
Median: 0.49
3rd quartile: 2.38
Max: 3.45

in ascending order.

0,0,0,0,0.03,0.13,0.15,0.18,0.25,0.27,0.29,0.29,0.36,0.46,0.52,0.53,0.58,0.83,0.93,1.29,2.16,2.6,2.65,2.77,2.83,2.92,3.14,3.45

MIN AND MAX Once the data is sorted, it's easy to see that the minimum data value is 0 and the maximum data value is 3.45.

MEDIAN

Since there is an even number of data values in this data set, there are two middle numbers. With 28 data values, the middle numbers are the data values at positions 14 and 15. These are 0.46 and 0.52. The median is the average of these numbers. We have

(0.46+0.52)/ 2= 0.49

Therefore, the median is0.49

Q1, the 25th percentile:

Since there is an even number of data values in this data set, there are two middle numbers. With 14 data values, the middle numbers are the data values at positions 7 and 8. These are 0.15 and 0.18. The median is the average of these numbers. We have

(0.15+0.18)/ 2 = 0.65

Therefore, Q1, the 25th percentile, is0.165

Q3, the 75th percentile

Since there is an even number of data values in this data set, there are two middle numbers. With 14 data values, the middle numbers are the data values at positions 7 and 8. These are 2.16 and 2.6. The median is the average of these numbers. We have

(2.16+2.62)/2 = 2.38

Therefore, Q3, the 75th percentile, is2.38