Question

1. The volume of a gas at 20°C and 1.00 bar adsorbed on the surface of 1.50g of a sample of silica at 0°C was 1.52 cm'at 56.4 kPa and 2.77 cm at 108 kPa. Determine the volume needed to form a monolayer. (1.5 points)

Answer 1

1) liver, The mass, m= 1.509 Ti = 20°c Tz zo'c. VE 1.52 cm? ; Pi = 56.4kPa. V₂ = 2,77cm? ; P2 = 108 kPa The fraction coverage by gaseous molecules is; The renase equation is voor 14KP zeying #p+' > 0 → Kp = 0 + 0 kp = 0 = KP(1-0) Kz * PCI-E. PC1- ) P2C1_Vi] V * VV

Pi (Vm-V). Pov P (Um-VI) Vi P2 (Vm-V2) va - - B piyang = B. Vm=FY i to =P, = bayan B. C 2) Vm = Piel P.-P2 56.4 - 108 (564 - 108 1 -5li6 kPa. (37.11 - 38.99) kPa.com] = -51.6 kPa -1.88 kPa cm3 Vm = 27.45 cm3. The volume needed by to form a monolayer is 27,45 em