Question

Substitution occurs more readily when a halide ion (eg cl from HCI) is present, resulting in the -OH group of the alcohol being replaced by a halogen atom. A strong acid is necessary, since the H* converts the -OH group into - OH2*, which can then be lost as a water molecule: CH3 H2C=C elimination CHą -H,,! CH3 CH3 CH3 CH3 H3C-Ć-OH H3C-Ć-ÖH2 + H2O + H3C-c@ сна CH? CH3 2-methyl-2-propanol C H3C-C-Cl a 3° carbocation substitution CH3 2-chloro-2-methylpropane Carbocations are unstable, slow to form, and extremely fast to react. Tertiary carbocations are the least unstable, so (as seen in this experiment) the elimination and substitution reactions occur quite readily. For the following questions, write down your answers (and working out and take them to class with you. You will use the same method in class to determine the number of moles used of the following substances during the practical.

Answer 1

Ans

Part A. 0.104g/mole of reactant 2-methyle -2- propanol required

Part B. 0.210 mole of HCl is required

Part C. 2-methyle- 2 -propanol is limiting reagent

Part D 0.104 mole of 2-choloro- 2-
(A)cn2---c -> с - metig-2-Propau 2 2-ehloro-2-msteg Propans A1eoha Volum X mass QASrty = 0715 1/ms donsity2-methy 2-Popamae volume 2-metyl-2- Propanel mass= 16X 0775 7-75 am mass (ga No mol 2-mut2ppne -2. moleudor 775 9/moe = |04 7412 Metaye 2-Propanee 104 a No. mol 2- moe B) No. et mo& Mo Hсo X =10 X 2 I) 000 O 210 mo o No nd 2l0 cs Scarmed with CamScanner

C. 2--en3 +He OH methy mo 2- 2- Pro pana Podue lest No 2-ehsoro - 2 - methy Propan 2-methy- 2 Propanoe Leui So ing ragant D No mo ln 2-enaoo- 2-mety Nmbar Propan aus anau to mol gan that o104 moe Lemi 2-eneoro-2 -methy So No mal Propans CS Scanned with CamScanner
methyle is formed