Question

Need help in C

(a) Write a C program to read in a line of text and count the occurrence of each English alphabet. The lowercase version of a letter is considered the same as the uppercase. To make viewing easy, the frequencies should be presented using a bar chart as follows. You can assume that the input contains only spaces, lowercase letters, uppercase letters and the newline character (i.e. the Enter key). Enter a line of text: Letter ZZz Erequency 0 (b) The following program includes array operations and pointers arithmetic operations. The program prints several values. The meaning of the first two values are given in the following.*' The value or content element index 3 of the array temp. The address of the element index 2 of the array temp. In one sentence, explain the meanings of each of the remaining four values, with reference to the array temp if appropriate. include <stdio.h> int mainO float temp[30] = {15.5, float ptri float copy-tempi 18.0, 17.6, 12.3, 15.4, 15.2, 13.5, 14.2); ptr-&temp [2]; printf("efin", temp[31) printf("edin", ptr) printf ("edIn",copy[5]) printf("%d\n", ptr + 1); printf("edIn", sizeof (temp[01)) printf ("8d\n", sizeof (copy))

Answer 1

Please let me know if you need further clarification on this.

(a).

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main(){
/*str is char array of size 200*/
char str[200];
/*to store the frequencies of each characters irrespective of small or caps*/
int frequency[26];

/*frequencies are initialized to 0*/
for(int i=0;i<26;i++){
frequency[i]=0;
}
printf("Enter a line of text: ");
scanf("%[^\t\n]s",str);

/*logic applied here, increase the frequency at i based on the character occur in the
string str. */
for(int i=0;i<strlen(str);i++){
if(str[i]>='A'&& str[i]<='Z'){
int ii=str[i]-'A';
frequency[ii]+=1;
}
if (str[i] >= 'a' && str[i] <= 'z') {
int ii = str[i] - 'a';
frequency[ii] += 1;
}
}
printf("\nLetter\tFrequency\n");
for(char i='A';i<='Z';i++){
printf("%c\t",i);
int k=i-'A';
for(int m=0;m<frequency[k];m++){
printf("*");
}
printf("\n");
}
  
return 0;
}

Sample input and output:

Enter a line of text: AAAAABBBBccccaaaDEFGXXXYYYzzz
Letter   Frequency
A   ********
B   ****
C   ****
D   *
E   *
F   *
G   *
H  
I  
J  
K  
L  
M  
N  
O  
P  
Q  
R  
S  
T  
U  
V  
W  
X   ***
Y   ***
Z   ***

?nt k-111-.A'i \r\n39 for(m-mfrequency[k]im+) 40 printf(\""\"" 41 42 printf(\""In) 43 45 return 0; 46 "",""error"":null,""modified"":1550859405,""source"":""automated""}"

To run the same program in Dev-C++: In dev c++ for loop do not allow to declare the the variables and initialize in it for().So to run the same program in devC++, look below changes made.

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main(){
/*str is char array of size 200*/
char str[200];
/*to store the frequencies of each characters irrespective of small or caps*/
int frequency[26];

/*frequencies are initialized to 0*/
int i=0;
for(i=0;i<26;i++){
   frequency[i]=0;
}
printf("Enter a line of text: ");
scanf("%[^\t\n]s",str);

/*logic applied here, increase the frequency at i based on the character occur in the
string str. */
for(i=0;i<strlen(str);i++){
   if(str[i]>='A'&& str[i]<='Z'){
       int ii=str[i]-'A';
       frequency[ii]+=1;
   }
if (str[i] >= 'a' && str[i] <= 'z') {
   int ii = str[i] - 'a';
   frequency[ii] += 1;
   }
}

char iii;
int m;
printf("\nLetter\tFrequency\n");

for(iii='A';iii<='Z';iii++){
   printf("%c\t",iii);
   int k=iii-'A';
   for(m=0;m<frequency[k];m++){
           printf("*");
   }
   printf("\n");
}
  
return 0;
}

$CAUsers ravib\Documentslmy.c [Executing] - Dev-C++5.11 e Edit earch View Project Execute Iools AStyle Window Help 凹 (globals)$

(b):

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main(){
float temp[30]={15.5,18.0,17.6,12.3,15.4,15.2,13.5,14.2};
float*ptr;
float*copy=temp;

ptr =&temp[2];
printf("%f\n",temp[3]);
printf("%d\n", ptr);
printf("**%d\n",&temp[5]);/*----The address of the element index 5 of the array temp */
printf("%d\n",copy[5]);/*----The value or content element index 5 of the array pointer copy*/
printf("%d\n",ptr+1); /*----The address of the element index 3 of the array temp*/
printf("%d\n",sizeof(temp[0]));/*----The size of the value or content element index 0 of the array temp*/
printf("%d\n", sizeof(copy));/*---Thie size of the value or content element of the array temp pointed by pointer copy.*/
return 0;
}

Answer:

printf("**%d\n",&temp[5]);/*----The address of the element index 5 of the array temp */
printf("%d\n",copy[5]);/*----The value or content element index 5 of the array pointer copy*/
printf("%d\n",ptr+1); /*----The address of the element index 3 of the array temp*/
printf("%d\n",sizeof(temp[0]));/*----The size of the value or content element index 0 of the array temp*/
printf("%d\n", sizeof(copy));/*---Thie size of the value or content element of the array temp pointed by pointer copy.*/

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