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An automobile suspension system is modeled as a 2-DoF vibration system as shown in Figure below

Derive the equation of motion


Determine the natural frequencies of the automobile with the following data


Mass (mm) = 1000kg1000kg


Momen of inertia (ImIm) = 450kgm2450kgm2


Distance between front axle and C.G. (LfLf) = 1.2m1.2m


Distance between rear axle and C.G. (LfLf) = 1.5m1.5m


Front spring stiffnes (kfkf) = 18kN/m18kN/m


Rear spring stiffnes (krkr) = 17kN/m17kN/m


Front damper coefficient (cfcf) = 3kNs/m3kNs/m


Rear damper coefficient (cfcf) = 2kNs/m

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Answer #1

Kinetic energy = 1 mx ² + 1 Imet potential energy & (x-2,0) + Į kq (x-2go) 2 Damped energy = £r (x-L6) + 1 c (A-Lyggt By Lagr

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