rd enthalpy of formation for compound WC(s) from Wis) and Clgraphite) is difficult to measure directly...
Determine the ethalpy of reaction, delta H, for the formation of tungsten carbide, WC, from the elements. W(s) + C(graphite) = WC (s) The heats of combustion of the elements and of tungsten carbide are: 2 W(s) + 3 O2 (g) = 2 WO3 (s); delta H = -1685.8 KJ C (graphite) + O2 (g) = CO2 (g); delta H = -393.5 KJ 2WC (s) + 5 O2 (g) = 2 WO3 (s) + 2 CO2 (g); delta H =...
Tungsten carbide (WC) is an extremely hard material that is often used to create or coat cutting tools. Calculate the enthalpy of formation of solid tungsten carbide from tungsten metal and graphite given the following three pieces of information. Show your full working clearly (7 points) (i) AHr (WO3)-842.9 k/mol )AH (CO2)-393.5 kJ/mol (i) 2 WC (s)5O2 (g)2 WOs (s)+2 CO2 () AHn-2391.8 k 4.
From the following heats of combustion, CH3OH(l) + 3/2O2(g) → CO2(g) + 2H2O(l) ΔHorxn = –726.4 kJ/mol C(graphite) + O2(g) → CO2(g) ΔHorxn = –393.5 kJ/mol H2(g) + ½O2(g) → H2O(l) ΔHorxn = –285.8 kJ/mol Calculate the enthalpy of formation of methanol (CH3OH) from its elements. C(graphite) + 2H2(g) + ½O2(g) → CH3OH(l) Methanol (CH3OH) is an organic solvent and is also used as a fuel in some automobile engines. From...
7- (15 pts) Calculate the standard enthalpy of formation of CS2 (1) given that a. C(s) + O2(g) + CO2(g) b. S(s) + O2(g) → SO2(e) C. CS2() + 302(g) → CO2(g) + ' 250 (6) AH° = -393.5 kJ/mol AH° = -296.4 kJ/mol AH° = -1073.6 kj/mol (the standard state of the element Sulfur is S(s))
The standard heat of formation, ΔH∘f, is defined as the enthalpy change for the formation of one mole of substance from its constituent elements in their standard states. Thus, elements in their standard states have ΔH∘f=0. Heat of formation values can be used to calculate the enthalpy change of any reaction. Consider, for example, the reaction 2NO(g)+O2(g)⇌2NO2(g) with heat of formation values given by the following table: Substance ΔH∘f (kJ/mol) NO(g) 90.2 O2(g) 0 NO2(g) 33.2 Then the standard heat...
The following table lists some enthalpy of formation values for selected substances. Substance ΔfH∘ΔfH∘ (kJ mol−1)(kJ mol−1) CO2(g)CO2(g) −393.5−393.5 Ca(OH)2(s)Ca(OH)2(s) −986.1−986.1 H2O(l)H2O(l) −285.8−285.8 CaCO3(s)CaCO3(s) −1207−1207 H2O(g)H2O(g) −241.8−241.8 Part A: Determine the enthalpy for this reaction: Ca(OH)2(s)+CO2(g)→CaCO3(s)+H2O(l) C a ( O H ) 2 ( s ) + C O 2 ( g ) → C a C O 3 ( s ) + H 2 O ( l ) Express your answer in kJ mol−1 k J m o l...
PROBLEM-SOLVING CLASS ACTIVITY 11 Use Hess's Law to calculate the enthalpy of formation of CH2OH: C(graphite) + 2 H2(g) + 1026) → CH2OH(1) Given the following data: CH2OH() • 02(9) + CO2(g) + 2H2O(1) AH°: -726.4 kJ/mol C(graphite). O2(g) → CO2(9) AH' = -393.5 kJ/mol H2(g) + 40269) → H2O(1) AH = -285.8 kJ/mol
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2. Use the following enthalpies of formation to calculate an approximate enthalpy of reaction, AHrxn for: (5 pts) C3H8 (g) + 502 (g) → 3CO2 (g) + 4 H20 (1) C(s) + O2 (g) - CO2 (g); AH = - 393.5 kJ/mol H2(g) + 42 02 (g) - H20 (1); AH = - 285.5 kJ/mol 3 C(s) + 4 H2(g) → C3H8 (g); AH r = - 103.8 kJ/mol
Calculate the standard enthalpy of formation of solid calcium oxide (CaO) using the following thermochemical information: CaO(s) + CO2(g) CaCO3(s) H = -178.3 kJ C(s) + O2(g) CO2(g) H = -393.5 kJ 2 C(s) + 2 Ca(s) + 3 O2(g) 2 CaCO3(s) H = -2413.8 kJ H = kJ
Calculate the standard enthalpy of formation of liquid water
(H2O) using the following thermochemical
information:
CH4(g) C(s) + 2 H2(g)
H = +74.8 kJ
CO2(g) C(s) + O2(g)
H = +393.5 kJ
CO2(g) + 2 H2O(l) CH4(g) + 2 O2(g)
H = +890.4 kJ