P(one person in a cab) = 0.60
P(2 people in a cab) = 0.30
P(3 people in a cab) = 0.10
P(at most 4 people leaving the hotel in 3 cabs) = P(1 person in each cab) + P(1 person each in 2 cabs and 2 people in one cab)
= P(1 person in each cab) + [P(1 person each in first and second can and 2 people in third cab) + P(1 person each in first and third cab and 2 people in second cab) + P(one person each in second and third cab and 2 people in first cab)
= 0.60x0.60x0.60 + [0.60x0.60x0.30 + 0.60x0.30x0.60 + 0.30x0.60x0.60]
= 0.60x0.60x0.60 + 3 x (0.6x0.6x0.30)
= 0.54
Example: Suppose Taxicab leaves the hotel with a group of passen- gers. The number of people...
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