Ans:
1)
mean=200
standard deviation=sqrt(200)=14.14
z=(220-200)/14.14
z=1.414
P(z>1.414)=0.079
Option A is correct.
2)
P(claim)=0.1*0.2+0.08*0.35+0.05*0.3+0.02*0.15=0.066
P(Tier I/claim)=0.1*0.2/0.066=0.30
Option B is correct(0.30)
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