Question

Could someone look over this for me and see if my answers are correct. Thanks.

Font Paragraph Styles Data Table 1: Model Air Bag Activity Data and Calculations 1.20 L Volume of 6x 9 inch bag Room temperature RT in K 22273- 295 K 30, . 25.4mm/1.00" * 1.00atm/760mm= 762/760= Room pressure (in atm) 1atm Moles of CO2 required to inflate bag at room temperature and pressure n-(1 atm 1.2L)/ (.0821 .05 moles 295K)-049 Balanced equation for the reaction of NaHCO and CHaCOOH Mass of NaHCOs needed for the reaction (84.0 g/mol) Volume of vinegar required (0.833 M acetic acid) NaHCo3+ CH3COOH >H20+CO2+CH3COONa 84.01g/1 mole HCO3 05 moles CO2.1 mol Ho03/1mol CO2 -4.2 grams 05mol CO2 1mol CH300H/1mol Co2)/(.833 mole CH3COOH/L) 1000ml/L-60.02 m Data Table 2: Model Air Bag

Answer 1