Question

Question 13 Calculate the number of moles of solute in each solution. 7.5L of 1.50 M NaOH = moles 0.500 L of 0.215 M HCI = moles

Answer 1

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Question 13 : we know that, - Molansity of No. of moles of solute Solution volume of the solution in Liters Thus, No. of moles of solute = molarity of solution x volume of the solution in Liters Now , 7.5 L of 1.50 M NaOH : No. of moles of solute = 75 X x 1.50 mol/x = 11.25 moles (Aus) 0.500 L No. of of o.215 M HU : moles of solute = 0-500 x x 0.215 molle = 0.1075 moles (Aus).