Question

A stream is primarily air (29 g/mole) with a small but measurable amount of methane (16 g/mole). the average molecular weight is: less than 16 more than 16 but less than 29 greater than 29 not enough information

0 0
Add a comment Improve this question Transcribed image text
Answer #1

ns if we have two mumbers a f b, then the average muut be in betiveeu a 4 b Molecula wtob stemn = 293)mol tme hune 16mol and

Add a comment
Know the answer?
Add Answer to:
A stream is primarily air (29 g/mole) with a small but measurable amount of methane (16...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A mixture of methane and air is capable of being ignited only if the mole pecent...

    A mixture of methane and air is capable of being ignited only if the mole pecent of methane is between 5% and 15%. A mixture containing 9.0mole% methane in air flowing at a rate of 700.kg/h is to be diluted with pure air to reduce the methane concentration to the lower flammability limit. Calculate the required flow rate of air in mol/h and the percent by mass of oxygen in the product gas. (note Air may be taken to consist...

  • A stream of methane at 192 kg/hr is burned in a boiler to heat water. The...

    A stream of methane at 192 kg/hr is burned in a boiler to heat water. The boiler is fed 45.13 excess air. What is the air flow rate in kgmol/hr? Note: Air can be treated to be 78 % N2, 21 % O2 and remainder percentage Argon, where all percentages are in mole percents. Average molecular weight for air of this composition is 28.970 kg/kgmol

  • A stream of methane at 120.90 kg/hr is burned in a boiling tank. The boiler is...

    A stream of methane at 120.90 kg/hr is burned in a boiling tank. The boiler is fed 37.30 % air, in excess. Solve for the water composition of the flue gas (wet basis), in mass percentage. Air can be treated to be 78 % N2, 21 % O2 and 1% Argon, where all percentages are in mole percents. The average molecular weight for air of this composition is 28.97 kg/kgmol

  • 3. Using the given conversion factors, calculate the residence time of methane in an atmospheric condition...

    3. Using the given conversion factors, calculate the residence time of methane in an atmospheric condition where the steady state influx concentration is 1.75 ppv and the total release of methane from all sources is 550 million tons per year [2000lbs- ton, 2.2 lbs-1 kg, average molecular weight of air molecules is 29 g/mol, total mass of the atmosphere = 5.27 x 10' kg ] {Hint: Residence time= [steady- state amount of substance in the reservoir][rate of inflow to (or...

  • Air is a mixture of (mostly) oxygen (molecular mass 16) and nitrogen (molecular mass 14) gases. At room temperature, wh...

    Air is a mixture of (mostly) oxygen (molecular mass 16) and nitrogen (molecular mass 14) gases. At room temperature, which molecules in this room have a greater speed (on average)? They are the same O Nitrogen Oxygen O Not enough information to tell Submit Answer Incorrect. Tries 1/2 Previous Tries

  • Questions 16-20 refer to the following situation: A heavy semi-truck collides head-on with a small

    Questions 16-20 refer to the following situation: A heavy semi-truck collides head-on with a small, light car \(\left(m_{\text {car }}<m_{\text {truck }}\right)\). Before the collision the vehicles were moving with the same speed but in opposite direction.During the collision, is the force that the car exerts on the truck greater, equal or less than the force that the truck exerts on the car?There is not enough information to determine the answer.It is greater than the force exerted by the truck...

  • Choose a small molecule drug (molecular weight < ~250 g/mole, fewer than 20 non-H atoms) a...

    Choose a small molecule drug (molecular weight < ~250 g/mole, fewer than 20 non-H atoms) a nurse might administer during a typical day at work. Write the chemical formula and draw the electron dot formula of the drug. You will probably want to do this with pencil and paper and post a snapshot of your work. Identify three central atoms in the molecule and using VSEPR theory and taking into account bond types and bond numbers and lone pairs of...

  • how do we determine the mass of acid/mole of sodium hydroxide of the unknown acid? i...

    how do we determine the mass of acid/mole of sodium hydroxide of the unknown acid? i am just looking for the formula to solve it D. Determination of the mass of an unknown acid required to neutralize one mole of hydroxide ion. Obtain a clean, dry capped shell vial containing an unknown acid. Record your unknown's number and label the vial. Keep this vial in your locker until your graded lab report has been returned to you. 1. Note: the...

  • me 22.4L 16) At STP, one mole of which gas has a greater volume? A) I...

    me 22.4L 16) At STP, one mole of which gas has a greater volume? A) I mole of helium @ STpmclar = B) I mole of hydrogen volume imce C) 1 mole of oxygen they all occupy the same volume it is impossible to tell from the information given 17) What is the volume (in liters) of 1.00 mole of krypton gas that has a pressure of 1.5 atm and a temperature of 25.0°C? (R=0.0821 L atm/mol K) A) 1.37...

  • Week 4 Process 1: Consider the process below: Water in Combustor Steam Generator Gas In Gas...

    Week 4 Process 1: Consider the process below: Water in Combustor Steam Generator Gas In Gas Out Combustor exit Steam Out A methane (CH) and air mixture is burnt in the combustor then the heat is recovered to produce steam. The CHa/air mixture comes in at 25°C and contains 10 kg/h of CH4 and 500 kg/h of air (assume 79% Nitrogen (N2) and 21 % Oxygen (O2)). The final outlet gas leaves at 100 °C. The combustion reaction follows the...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT