Assume a transparent rod of diameter d = 6.55
Assume a transparent rod of diameter d = 6.55
Homework Answers
X=theta
Critical angle is
Xc=sin^-1(n_air/n_rod)
Xc =sin^-1(1/1.34)
Xc=48.27 degrees
The angle of reflection is
Xr =90-48.27 =41.73 degrees
Incident angle is
from snells law
Xi =sin^-1(n_rod*sin(xr)/n_air)
Xi =sin^-1(1.34*sin41.73/1)
Xi=63.12 degrees
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