Question

Given that the standard concentration formula is (M₁V₁=M₂V₂₎ and the Cu initial concentration is 63.55 mg/mL plus data table info:

What would be V_{1 and} V_{2? Please show 2 examples from data table info.}

Solution	Starting buret read.	Ending buret read.	Total Delivered	concentration
1 mL	22.89 mL	23.91 mL	1.02 mL	?
2 mL	15.51 mL	17.49 mL	1.98 mL	?
4 mL	17.49 mL	21.69 mL	4.20 mL	?
6 mL	11.91 mL	17.92 mL	6.01 mL	?
8 mL	13.59 mL	21.56 mL	7.97 mL	?

Answer 1

Lets consider the 1st and the 4th readings.

In the first reading, M1 = 63.55 mg/ml, V1= 1.02 ml, V2 = 1ml

M1*V1 = M2*V2

63.55*1.02 = M2*1

M2 = 64.821 mg/ml

In the fourth reading, M1=63.55mg/ml, V1= 4.2ml, V2 = 4ml

M1*V1 = M2*V2

63.55 * 4.2 = M2 * 4

M2 = 66.727 mg/ml