Homework Answers
16. Energy emitted in the n=4 to n=2 transition of H atom
= h*c*(1.097*107)(1/4 - 1/16) = 4.0886 x 10-19 J
The Sign is Positive. Hence, Energy is emitted during the Transition.
17.a) The Electron configuration of Phosphorus is :
1s22s22p63s23p3
18. a) Increasing Order of Atomic Radius is :
F<Cl<P<Na
b) Increasing Order of Elecetronegativity is :
Na<P<Cl<F
c) Increasing Order of Ionisation energy is :
Na<P<Cl<F
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