Question

Assembly language. You can see the question in blue box.

Loop Instruction Problem 4: Write and run a program and answer the questions in the box. .data temp dword? First, build and run the program .code - Trace ECX value mov eax,0 ECX=? mov ecx, 10 ; outer loop counter - EAX =? L1: Second: If we removed mov ecx, temp mov eax, 3 What will happen? mov temp.ecx mov ecx,5 ; inner loop counter - build and run the program L2: - Report the result Third: Replace mov temp, ecx with push exc and add eax,5 mov ecx, temp with pop ecx, loop L2 ; repeat inner loop build the program and run it, trace the mov ecx, temp stack memory loop L1 repeat outer loop

Answer 1

Greetings!!

First:

ECX:

• Within the inner loop ECX goes from 5 to 0 and in the outer loop it goes from 10 to 0. After the execution, ECX has 0 in it.

EAX:

• Within the inner loop, eax is added with 3+5+5+5+5+5=28₁₀=1C₁₆

Second:

• Enters into inifinite loop because the outer loop reinitialize ECX to 5

Third:

• Produces the result as in first. Contains eax=1CH
• PUSH ECX saves the ecx onto the stack and reload it when uses POP ECX. Initial push operation save 10 onto the stack and next time it saves 9 and next time 8(LOOP instuction decrements ECX everytime.)

Hope this helps

Thank You